What is the sum from n=0 to infinity of (1.1)^n ?

The sum from n=0 to infinity of (1.1)^n is diverges

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sum from n=0 to infinity of (1.1)^n

n = 0 \sum \infty (1.1)^{n}

diverges

Solution steps

n = 0 \sum \infty 1. 1^{n}

Apply Series Geometric Test:

diverges

= diverges

y = arctan (x^{2} + 1)

\int \frac{1}{( 2 - x ) ( 3 - x )} d x

x \to 5 lim (\frac{x - 25}{x - 5})

x y d x + y^{2} d y = 0

f (x) = x^{3} - 4 x + 6

What is the sum from n=0 to infinity of (1.1)^n ?
The sum from n=0 to infinity of (1.1)^n is diverges