What is the derivative of f(x)=x^3-4x+6 ?

The derivative of f(x)=x^3-4x+6 is 3x^2-4

What is the first derivative of f(x)=x^3-4x+6 ?

The first derivative of f(x)=x^3-4x+6 is 3x^2-4

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derivative of

f (x) = x^{3} - 4 x + 6

3 x^{2} - 4

Solution steps

\frac{d}{d x} (x^{3} - 4 x + 6)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (6)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (6) = 0

= 3 x^{2} - 4 + 0

Simplify

= 3 x^{2} - 4

\frac{d}{d x} (\frac{x ^{2}}{1 + e ^{x}})

\int \frac{10 x ^{2}}{x ^{4} - 1} d x

n = 5 \sum \infty (\frac{4}{5})^{n}

\int 4 x^{3} (4 + x^{4})^{\frac{1}{3}} d x

\frac{r}{r ^{2} + 4}

What is the derivative of f(x)=x^3-4x+6 ?
The derivative of f(x)=x^3-4x+6 is 3x^2-4
What is the first derivative of f(x)=x^3-4x+6 ?
The first derivative of f(x)=x^3-4x+6 is 3x^2-4