What is the sum from n=5 to infinity of (4/5)^n ?

The sum from n=5 to infinity of (4/5)^n is converges

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sum from n=5 to infinity of (4/5)^n

n = 5 \sum \infty (\frac{4}{5})^{n}

converges

Solution steps

n = 5 \sum \infty (\frac{4}{5})^{n}

Apply Series Ratio Test:

converges

= converges

\int 4 x^{3} (4 + x^{4})^{\frac{1}{3}} d x

\frac{r}{r ^{2} + 4}

x \frac{d y}{d x} = x^{3} + 4 x^{3} y

n = 1 \sum \infty \frac{n 5 ^{n}}{n !}

5 tan (x)

What is the sum from n=5 to infinity of (4/5)^n ?
The sum from n=5 to infinity of (4/5)^n is converges