What is the integral of (2xy-tan(y)) ?

The integral of (2xy-tan(y)) is -tan(y)x+yx^2+C

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integral of (2xy-tan(y))

\int (2 x y - tan (y)) d x

- tan (y) x + y x^{2} + C

Solution steps

\int 2 x y - tan (y) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int tan (y) d x + \int 2 y x d x

\int tan (y) d x = tan (y) x

\int 2 y x d x = y x^{2}

= - tan (y) x + y x^{2}

Add a constant to the solution

= - tan (y) x + y x^{2} + C

\frac{d}{d x} (9 e^{- x} + e^{2 x})

y = cos (x), y = 2 - cos (x)

\frac{d}{d x} (3 x + 2)

\int 2 - 2 cos (x) d x

\frac{1}{3} x^{3} - 4 x^{2} + 17 x + 13

What is the integral of (2xy-tan(y)) ?
The integral of (2xy-tan(y)) is -tan(y)x+yx^2+C