What is the derivative of 9e^{-x}+e^{2x} ?

The derivative of 9e^{-x}+e^{2x} is -9e^{-x}+e^{2x}*2

What is the first derivative of 9e^{-x}+e^{2x} ?

The first derivative of 9e^{-x}+e^{2x} is -9e^{-x}+e^{2x}*2

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\frac{d}{d x} (9 e^{- x} + e^{2 x})

- 9 e^{- x} + e^{2 x} \cdot 2

Solution steps

\frac{d}{d x} (9 e^{- x} + e^{2 x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9 e^{- x}) + \frac{d}{d x} (e^{2 x})

\frac{d}{d x} (9 e^{- x}) = - 9 e^{- x}

\frac{d}{d x} (e^{2 x}) = e^{2 x} \cdot 2

= - 9 e^{- x} + e^{2 x} \cdot 2

y = cos (x), y = 2 - cos (x)

\frac{d}{d x} (3 x + 2)

\int 2 - 2 cos (x) d x

\frac{1}{3} x^{3} - 4 x^{2} + 17 x + 13

\int 5 e^{8 - 4 x} - 5 d x

What is the derivative of 9e^{-x}+e^{2x} ?
The derivative of 9e^{-x}+e^{2x} is -9e^{-x}+e^{2x}*2
What is the first derivative of 9e^{-x}+e^{2x} ?
The first derivative of 9e^{-x}+e^{2x} is -9e^{-x}+e^{2x}*2