What is the integral of 5e^{8-4x}-5 ?

The integral of 5e^{8-4x}-5 is -5/4 e^{8-4x}-5x+C

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integral of 5e^{8-4x}-5

\int 5 e^{8 - 4 x} - 5 d x

- \frac{5}{4} e^{8 - 4 x} - 5 x + C

Solution steps

\int 5 e^{8 - 4 x} - 5 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 e^{8 - 4 x} d x - \int 5 d x

\int 5 e^{8 - 4 x} d x = - \frac{5}{4} e^{8 - 4 x}

\int 5 d x = 5 x

= - \frac{5}{4} e^{8 - 4 x} - 5 x

Add a constant to the solution

= - \frac{5}{4} e^{8 - 4 x} - 5 x + C

\frac{\partial}{\partial x} (∣ A x ∣^{2})

f (x) = e^{- 3.5 x^{2}}

\int \frac{1}{n ^{2}}

\frac{d}{d x} ((x^{2} - 1)^{5})

y^{^{''}} - 289 y = 0

What is the integral of 5e^{8-4x}-5 ?
The integral of 5e^{8-4x}-5 is -5/4 e^{8-4x}-5x+C