What is the derivative of f(x)=e^{-3.5x^2} ?

The derivative of f(x)=e^{-3.5x^2} is -7e^{-3.5x^2}x

What is the first derivative of f(x)=e^{-3.5x^2} ?

The first derivative of f(x)=e^{-3.5x^2} is -7e^{-3.5x^2}x

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derivative of

f (x) = e^{- 3.5 x^{2}}

- 7 e^{- 3.5 x^{2}} x

Solution steps

\frac{d}{d x} (e^{- 3.5 x^{2}})

Apply the chain rule:

e^{- 3.5 x^{2}} \frac{d}{d x} (- 3.5 x^{2})

= e^{- 3.5 x^{2}} \frac{d}{d x} (- 3.5 x^{2})

\frac{d}{d x} (- 3.5 x^{2}) = - 7 x

= e^{- 3.5 x^{2}} (- 7 x)

Simplify

= - 7 e^{- 3.5 x^{2}} x

\int \frac{1}{n ^{2}}

\frac{d}{d x} ((x^{2} - 1)^{5})

y^{^{''}} - 289 y = 0

\frac{d}{d x} (2 cos (sin (x)))

y = 2 x^{2} + \frac{3}{x}

What is the derivative of f(x)=e^{-3.5x^2} ?
The derivative of f(x)=e^{-3.5x^2} is -7e^{-3.5x^2}x
What is the first derivative of f(x)=e^{-3.5x^2} ?
The first derivative of f(x)=e^{-3.5x^2} is -7e^{-3.5x^2}x