What is the integral of (5x^2+6x-8) ?

The integral of (5x^2+6x-8) is (5x^3)/3+3x^2-8x+C

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integral of (5x^2+6x-8)

\int (5 x^{2} + 6 x - 8) d x

\frac{5 x ^{3}}{3} + 3 x^{2} - 8 x + C

Solution steps

\int 5 x^{2} + 6 x - 8 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 5 x^{2} d x + \int 6 x d x - \int 8 d x

\int 5 x^{2} d x = \frac{5 x ^{3}}{3}

\int 6 x d x = 3 x^{2}

\int 8 d x = 8 x

= \frac{5 x ^{3}}{3} + 3 x^{2} - 8 x

Add a constant to the solution

= \frac{5 x ^{3}}{3} + 3 x^{2} - 8 x + C

\int \frac{( x ^{4} + 8 )}{x ^{3}} d x

\frac{8}{x}

\int tan (9 x se) c^{2} 9 x d x

\frac{d y}{d x} = \frac{( x - 1 )}{y - 3}

\int \frac{1}{4 - 5 x} d x

What is the integral of (5x^2+6x-8) ?
The integral of (5x^2+6x-8) is (5x^3)/3+3x^2-8x+C