What is the solution for (3+3x^2)(dy)/(dx)+2xy=2xy^4 ?

The solution for (3+3x^2)(dy)/(dx)+2xy=2xy^4 is y=\sqrt[3]{1/(-x^2e^{3c_{1)}-e^{3c_{1}}+1}}

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(3+3x^2)(dy)/(dx)+2xy=2xy^4

(3 + 3 x^{2}) \frac{d y}{d x} + 2 x y = 2 x y^{4}

y = 3 \frac{1}{- x ^{2} e ^{3 c_{1}} - e ^{3 c_{1}} + 1}

Solution steps

(3 + 3 x^{2}) \frac{d y}{d x} + 2 x y = 2 x y^{4}

Solve Bernoulli ODE:

y = 3 \frac{1}{- x ^{2} e ^{3 c_{1}} - e ^{3 c_{1}} + 1}

y = 3 \frac{1}{- x ^{2} e ^{3 c_{1}} - e ^{3 c_{1}} + 1}

f (x) = ln (2)

\int 3 e^{4} d x

2000 (1 + \frac{r}{12})^{60}

f (x) = \frac{1}{x}, (a, \frac{1}{a})

3 x (x^{3} - 7 x + 4)

What is the solution for (3+3x^2)(dy)/(dx)+2xy=2xy^4 ?
The solution for (3+3x^2)(dy)/(dx)+2xy=2xy^4 is y=\sqrt[3]{1/(-x^2e^{3c_{1)}-e^{3c_{1}}+1}}