What is the integral from 5 to 9 of 2/(x^3) ?

The integral from 5 to 9 of 2/(x^3) is 56/2025

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integral from 5 to 9 of 2/(x^3)

\int_{5}^{9} \frac{2}{x ^{3}} d x

\frac{56}{2025}

Decimal

0.02765 \dots

Solution steps

\int_{5}^{9} \frac{2}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{5}^{9} \frac{1}{x ^{3}} d x

Apply the Power Rule

: [- \frac{1}{2 x ^{2}}]_{5}^{9}

= 2 [- \frac{1}{2 x ^{2}}]_{5}^{9}

Compute the boundaries:

\frac{28}{2025}

= 2 \cdot \frac{28}{2025}

Simplify

= \frac{56}{2025}

\int e^{3 x} 1 + 2 e^{3 x} d x

\frac{\partial}{\partial x} (1 - 2 x^{2} - 2 y)

(1 - t^{2}) y^{^{''}} - 2 t y^{^{'}} + 2 y = 0

\frac{d}{d x} ((x + a) e^{2 x})

\int_{0}^{4} x e^{x} d x

What is the integral from 5 to 9 of 2/(x^3) ?
The integral from 5 to 9 of 2/(x^3) is 56/2025