What is laplacetransform e^tsin(t) ?

The answer to laplacetransform e^tsin(t) is 1/((s-1)^2+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform e^tsin(t)

laplace transform

e^{t} sin (t)

\frac{1}{( s - 1 ) ^{2} + 1}

Solution steps

L {e^{t} sin (t)}

Apply transform rule:

L {f (t)} = F (s)

then

L {e^{a t} f (t)} = F (s - a)

For

e^{t} sin (t) : f (t) = sin (t), a = 1

= L {sin (t)} (s - 1)

L {sin (t)} : \frac{1}{s ^{2} + 1}

= \frac{1}{( s - 1 ) ^{2} + 1}

\frac{\partial}{\partial x} (4 x^{- \frac{1}{8}})

\int 3 x^{2} e^{- 3 x} d x

\frac{d}{d x} (6 x^{2} (4 x^{5} - 3 x + 2))

x \to 0 + lim (x^{3} (ln (x))^{2})

y = x (1 + x^{2})^{10}

What is laplacetransform e^tsin(t) ?
The answer to laplacetransform e^tsin(t) is 1/((s-1)^2+1)