What is the tangent of y=ln(x/2),\at x=4 ?

The tangent of y=ln(x/2),\at x=4 is y= 1/4 x+ln(2)-1

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tangent of y=ln(x/2),\at x=4

tangent of

y = ln (\frac{x}{2}), at x = 4

y = \frac{1}{4} x + ln (2) - 1

Solution steps

Find the tangent point:

(4, ln (2))

Find the slope of

y = ln (\frac{x}{2}) : \frac{d y}{d x} = \frac{1}{x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(4, ln (2)) : y = \frac{1}{4} x + ln (2) - 1

y = \frac{1}{4} x + ln (2) - 1

\int \frac{t ^{2}}{t + 1} d t

\frac{d}{d x} (l x)

\frac{d}{d x} (arccos (- 3 x))

y^{^{''}} + 16 = 0

\frac{d}{d x} \frac{( e ^{- x^{2}} )}{x ^{3}}

What is the tangent of y=ln(x/2),\at x=4 ?
The tangent of y=ln(x/2),\at x=4 is y= 1/4 x+ln(2)-1