What is the derivative of x^3-3x+5 ?

The derivative of x^3-3x+5 is 3x^2-3

What is the first derivative of x^3-3x+5 ?

The first derivative of x^3-3x+5 is 3x^2-3

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\frac{d}{d x} (x^{3} - 3 x + 5)

3 x^{2} - 3

Solution steps

\frac{d}{d x} (x^{3} - 3 x + 5)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (5)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (5) = 0

= 3 x^{2} - 3 + 0

Simplify

= 3 x^{2} - 3

n = 1 \sum \infty e^{- \frac{3}{n ^{2}}}

\int_{1}^{\infty} \frac{3}{x ^{2} + 1} d x

\int \frac{( 2 x + 1 )}{x} d x

n = 8 \sum \infty (\frac{7}{8})^{- n}

\frac{\partial}{\partial z} (x^{3} + y z^{2})

What is the derivative of x^3-3x+5 ?
The derivative of x^3-3x+5 is 3x^2-3
What is the first derivative of x^3-3x+5 ?
The first derivative of x^3-3x+5 is 3x^2-3