What is taylor \sqrt[3]{x} ?

The answer to taylor \sqrt[3]{x} is 1+1/3 (x-1)-1/9 (x-1)^2+5/81 (x-1)^3-10/243 (x-1)^4+\ldots

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

taylor \sqrt[3]{x}

taylor

1 + \frac{1}{3} (x - 1) - \frac{1}{9} (x - 1)^{2} + \frac{5}{81} (x - 1)^{3} - \frac{10}{243} (x - 1)^{4} + \dots

Solution steps

Apply the Taylor Formula

Evaluate Derivatives

= 1 + \frac{\frac{1}{3}}{1 !} (x - 1) + \frac{- \frac{2}{9}}{2 !} (x - 1)^{2} + \frac{\frac{10}{27}}{3 !} (x - 1)^{3} + \frac{- \frac{80}{81}}{4 !} (x - 1)^{4} + \dots

Refine

= 1 + \frac{1}{3} (x - 1) - \frac{1}{9} (x - 1)^{2} + \frac{5}{81} (x - 1)^{3} - \frac{10}{243} (x - 1)^{4} + \dots

f (x) = \frac{2}{x}, at x = - 5

\int_{0}^{1} x^{- \frac{1}{3}} d x

\int 4 x^{3} e^{2 x} d x

\int \frac{17.6 \cdot 15.24}{17.6 \cdot 0 ^{2} + 1}

x \to 0 lim (4 x^{2} + 3)

What is taylor \sqrt[3]{x} ?
The answer to taylor \sqrt[3]{x} is 1+1/3 (x-1)-1/9 (x-1)^2+5/81 (x-1)^3-10/243 (x-1)^4+\ldots