What is derivative of f(x)=3z(2z^2-7z+1)^4 ?

The answer to derivative of f(x)=3z(2z^2-7z+1)^4 is (dz)/(dx)=0

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derivative of f(x)=3z(2z^2-7z+1)^4

derivative of

f (x) = 3 z (2 z^{2} - 7 z + 1)^{4}

\frac{d z}{d x} = 0

Solution steps

f (x) = 3 z (2 z^{2} - 7 z + 1)^{4}

Treat

z

z (x)

Differentiate both sides:

0 = 3 (\frac{d z}{d x} (2 z^{2} - 7 z + 1)^{4} + 4 (2 z^{2} - 7 z + 1)^{3} (4 z \frac{d z}{d x} - 7 \frac{d z}{d x}) z)

Isolate

\frac{d z}{d x} : \frac{d z}{d x} = 0

\frac{d z}{d x} = 0

k = 1 \sum \infty k (\frac{2}{3})^{k}

sin (t - 1)

\int x^{2} (5 x^{3} + 7 x^{2} - 6 x - 3) d x

sin (2 x) d x + cos (3 y) d y = 0, y (\frac{π}{2}) = \frac{π}{3}

\int \frac{4}{( 1 - x ^{2} ) ^{\frac{3}{2}}} d x

What is derivative of f(x)=3z(2z^2-7z+1)^4 ?
The answer to derivative of f(x)=3z(2z^2-7z+1)^4 is (dz)/(dx)=0