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Popular >

2y^'=3t+2

Solution

2 y^{^{'}} = 3 t + 2

Solution

y = \frac{3 t ^{2}}{4} + t + c_{1}

Solution steps

2 y^{'} (t) = 3 t + 2

Isolate

y^{'} (t) : y^{'} (t) = \frac{3 t + 2}{2}

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int \frac{3 t + 2}{2} d t

\int \frac{3 t + 2}{2} d t = \frac{3 t ^{2}}{4} + t + c_{1}

y = \frac{3 t ^{2}}{4} + t + c_{1}

Graph

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n \to \infty lim (3^{- n})

derivative of y=(x^3-2)^2 derivative of

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Frequently Asked Questions (FAQ)

What is the solution for 2y^'=3t+2 ?
The solution for 2y^'=3t+2 is y=(3t^2)/4+t+c_{1}