What is the derivative of y=(x^3-2)^2 ?

The derivative of y=(x^3-2)^2 is 6x^2(x^3-2)

What is the first derivative of y=(x^3-2)^2 ?

The first derivative of y=(x^3-2)^2 is 6x^2(x^3-2)

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derivative of

y = (x^{3} - 2)^{2}

6 x^{2} (x^{3} - 2)

Solution steps

\frac{d}{d x} ((x^{3} - 2)^{2})

Apply the chain rule:

2 (x^{3} - 2) \frac{d}{d x} (x^{3} - 2)

= 2 (x^{3} - 2) \frac{d}{d x} (x^{3} - 2)

\frac{d}{d x} (x^{3} - 2) = 3 x^{2}

= 2 (x^{3} - 2) \cdot 3 x^{2}

Simplify

= 6 x^{2} (x^{3} - 2)

(x)^{(\frac{1}{3})}

\frac{\partial}{\partial x} (x^{7} y z^{2} + 3 yz)

\frac{d}{d x} (4 sin (5 x))

y = - x, y = \frac{1}{2} x - \frac{3}{2}, x = - 1, x = 3

\int_{0}^{1} x - x^{3} d x

What is the derivative of y=(x^3-2)^2 ?
The derivative of y=(x^3-2)^2 is 6x^2(x^3-2)
What is the first derivative of y=(x^3-2)^2 ?
The first derivative of y=(x^3-2)^2 is 6x^2(x^3-2)