What is the derivative of 4sin(5x) ?

The derivative of 4sin(5x) is 20cos(5x)

What is the first derivative of 4sin(5x) ?

The first derivative of 4sin(5x) is 20cos(5x)

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\frac{d}{d x} (4 sin (5 x))

20 cos (5 x)

Solution steps

\frac{d}{d x} (4 sin (5 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (sin (5 x))

Apply the chain rule:

cos (5 x) \frac{d}{d x} (5 x)

= cos (5 x) \frac{d}{d x} (5 x)

\frac{d}{d x} (5 x) = 5

= 4 cos (5 x) \cdot 5

Simplify

= 20 cos (5 x)

y = - x, y = \frac{1}{2} x - \frac{3}{2}, x = - 1, x = 3

\int_{0}^{1} x - x^{3} d x

y^{^{'}} (1 + x^{2}) + (1 + y^{2}) = 0

\int - \frac{2 x}{3} + 2 d x

x \to - 2 + lim (\frac{2}{x ^{2} - 4})

What is the derivative of 4sin(5x) ?
The derivative of 4sin(5x) is 20cos(5x)
What is the first derivative of 4sin(5x) ?
The first derivative of 4sin(5x) is 20cos(5x)