What is area y=-x,y= 1/2 x-3/2 ,x=-1,x=3 ?

The answer to area y=-x,y= 1/2 x-3/2 ,x=-1,x=3 is 6

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area y=-x,y= 1/2 x-3/2 ,x=-1,x=3

area

y = - x, y = \frac{1}{2} x - \frac{3}{2}, x = - 1, x = 3

6

Solution steps

Apply the area formula:

\int_{- 1}^{3} \frac{3}{2} x - \frac{3}{2} d x

Solve

\int_{- 1}^{3} \frac{3}{2} x - \frac{3}{2} d x : 6

The area is:

= 6

\int_{0}^{1} x - x^{3} d x

y^{^{'}} + (1 + y^{2}) = 0

\int - \frac{2 x}{3} + 2 d x

x \to - 2 + lim (\frac{2}{x ^{2} - 4})

x \frac{d y}{d x} + y = x^{4} y^{3}

What is area y=-x,y= 1/2 x-3/2 ,x=-1,x=3 ?
The answer to area y=-x,y= 1/2 x-3/2 ,x=-1,x=3 is 6