What is the d/(dθ)(asin(θ)) ?

The d/(dθ)(asin(θ)) is acos(θ)

What is the first d/(dθ)(asin(θ)) ?

The first d/(dθ)(asin(θ)) is acos(θ)

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\frac{d}{d θ} (a sin (θ))

a cos (θ)

Solution steps

\frac{d}{d θ} (a sin (θ))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= a \frac{d}{d θ} (sin (θ))

Apply the common derivative:

\frac{d}{d θ} (sin (θ)) = cos (θ)

= a cos (θ)

\frac{d}{d x} (3 x y^{3})

y^{^{''}} = - 9 sin (5 x)

\frac{\partial}{\partial x} (\frac{2}{x} - n)

\int (8 t^{3} - 6 t^{- 2}) d t

x \to - 1^{- 1} lim (\frac{x}{x + 1})