What is the integral from 1 to 2 of ((8-x^2))/(x^3) ?

The integral from 1 to 2 of ((8-x^2))/(x^3) is 3-ln(2)

Popular >

integral from 1 to 2 of ((8-x^2))/(x^3)

\int_{1}^{2} \frac{( 8 - x ^{2} )}{x ^{3}} d x

3 - ln (2)

Decimal

2.30685 \dots

Solution steps

\int_{1}^{2} \frac{8 - x ^{2}}{x ^{3}} d x

Expand

\frac{8 - x ^{2}}{x ^{3}} : \frac{8}{x ^{3}} - \frac{1}{x}

= \int_{1}^{2} \frac{8}{x ^{3}} - \frac{1}{x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{8}{x ^{3}} d x - \int_{1}^{2} \frac{1}{x} d x

\int_{1}^{2} \frac{8}{x ^{3}} d x = 3

\int_{1}^{2} \frac{1}{x} d x = ln (2)

= 3 - ln (2)

x \to 0 lim (\frac{\frac{2}{x + 2} - 1}{x})

e^{t^{2}} y^{^{'}} + t + t y^{2} = 0

x \to 0 + lim (5 x^{2} ln (x))

f (x) = 4 x^{4}

(5.4) (- 1.6)

What is the integral from 1 to 2 of ((8-x^2))/(x^3) ?
The integral from 1 to 2 of ((8-x^2))/(x^3) is 3-ln(2)