What is the solution for e^{t^2}y^'+t+ty^2=0 ?

The solution for e^{t^2}y^'+t+ty^2=0 is y=tan(1/2 e^{-t^2}+c_{1})

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e^{t^2}y^'+t+ty^2=0

e^{t^{2}} y^{^{'}} + t + t y^{2} = 0

y = tan (\frac{1}{2} e^{- t^{2}} + c_{1})

Solution steps

e^{t^{2}} y^{'} (t) + t + t y^{2} = 0

Solve separable ODE:

y = tan (\frac{1}{2} e^{- t^{2}} + c_{1})

y = tan (\frac{1}{2} e^{- t^{2}} + c_{1})

x \to 0 + lim (5 x^{2} ln (x))

f (x) = 4 x^{4}

(5.4) (- 1.6)

\int - x e^{x} d x

x \to 0 - lim (6 - \frac{1}{x ^{3}})

What is the solution for e^{t^2}y^'+t+ty^2=0 ?
The solution for e^{t^2}y^'+t+ty^2=0 is y=tan(1/2 e^{-t^2}+c_{1})