What is the limit as x approaches 0-of 6-1/(x^3) ?

The limit as x approaches 0-of 6-1/(x^3) is infinity

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limit as x approaches 0-of 6-1/(x^3)

x \to 0 - lim (6 - \frac{1}{x ^{3}})

\infty

Solution steps

x \to 0 - lim (6 - \frac{1}{x ^{3}})

x \to a lim [f (x) \pm g (x)] = x \to a lim f (x) \pm x \to a lim g (x)

With the exception of indeterminate form

= x \to 0 - lim (6) - x \to 0 - lim (\frac{1}{x ^{3}})

x \to 0 - lim (6) = 6

x \to 0 - lim (\frac{1}{x ^{3}}) = - \infty

= 6 - (- \infty)

Simplify

6 - (- \infty) : \infty

= \infty

\int \frac{ln ( p + 1 )}{p + 1} d p

x \to 0 lim (\frac{1}{1 + e ^{\frac{1}{x}}})

\frac{d}{d x} (arcsin (\frac{x}{x + y}))

y^{^{'}} = \frac{( x ^{2} + y ^{2} )}{( 2 x y )}

f (x) = ∣ 2 x - 1 ∣

What is the limit as x approaches 0-of 6-1/(x^3) ?
The limit as x approaches 0-of 6-1/(x^3) is infinity