What is the limit as x approaches 0 of 1/(1+e^{1/x)} ?

The limit as x approaches 0 of 1/(1+e^{1/x)} is diverges

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limit as x approaches 0 of 1/(1+e^{1/x)}

x \to 0 lim (\frac{1}{1 + e ^{\frac{1}{x}}})

diverges

Solution steps

x \to 0 lim (\frac{1}{1 + e ^{\frac{1}{x}}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 0 + lim (\frac{1}{1 + e ^{\frac{1}{x}}}) = 0

x \to 0 - lim (\frac{1}{1 + e ^{\frac{1}{x}}}) = 1

= diverges

\frac{d}{d x} (arcsin (\frac{x}{x + y}))

y^{^{'}} = \frac{( x ^{2} + y ^{2} )}{( 2 x y )}

f (x) = ∣ 2 x - 1 ∣

y^{^{'}} + 5 y = 6 e^{x}

\frac{\partial}{\partial y} (2 y + z)

What is the limit as x approaches 0 of 1/(1+e^{1/x)} ?
The limit as x approaches 0 of 1/(1+e^{1/x)} is diverges