What is the tangent of f(x)=2x^2-x^4,\at x=1 ?

The tangent of f(x)=2x^2-x^4,\at x=1 is y=1

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tangent of f(x)=2x^2-x^4,\at x=1

tangent of

f (x) = 2 x^{2} - x^{4}, at x = 1

y = 1

Solution steps

Find the tangent point:

(1, 1)

Find the slope of

f (x) = 2 x^{2} - x^{4} : \frac{df ( x )}{d x} = 4 x - 4 x^{3}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(1, 1) : y = 1

y = 1

n = 0 \sum \infty (0.9)^{n}

\int \frac{1}{3 sin ( x ) + 4 cos ( x ) + 4} d x

\frac{\partial}{\partial x} (x + y + z^{2})

e^{- 11 x}

\int (4 - x^{2})^{2} d x

What is the tangent of f(x)=2x^2-x^4,\at x=1 ?
The tangent of f(x)=2x^2-x^4,\at x=1 is y=1