en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area 4-x^2,0,2

Solution

area

4 - x^{2}, 0, 2

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} 4 - x^{2} d x

Solve

\int_{0}^{2} 4 - x^{2} d x : \frac{16}{3}

The area is:

= \frac{16}{3}

Graph

Popular Examples

limit as x approaches pi/2 of sin(2x)

x \to \frac{π}{2} lim (sin (2 x))

integral of (2x-5)/(x^2+9)

\int \frac{2 x - 5}{x ^{2} + 9} d x

(\partial)/(\partial x)(6x^8y^6+2x^7y^5)

\frac{\partial}{\partial x} (6 x^{8} y^{6} + 2 x^{7} y^{5})

t^3y^'+4t^2y=e^{-t},y(1)=0

t^{3} y^{^{'}} + 4 t^{2} y = e^{- t}, y (1) = 0

taylor x^{-2},9 taylor

x^{- 2}, 9

Frequently Asked Questions (FAQ)

What is area 4-x^2,0,2 ?
The answer to area 4-x^2,0,2 is 16/3