What is the tangent of x^2+y^2=25,(3,4) ?

The tangent of x^2+y^2=25,(3,4) is y=-3/4 x+25/4

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tangent of x^2+y^2=25,(3,4)

tangent of

x^{2} + y^{2} = 25, (3, 4)

y = - \frac{3}{4} x + \frac{25}{4}

Solution steps

Find the slope of

x^{2} + y^{2} = 25 : \frac{d y}{d x} = - \frac{x}{y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{3}{4}

Find the line with slope m=

- \frac{3}{4}

and passing through

(3, 4) : y = - \frac{3}{4} x + \frac{25}{4}

y = - \frac{3}{4} x + \frac{25}{4}

\frac{\partial}{\partial x} (- 9 x^{2} - 7 y^{2})

y^{^{''}} + 169 y = sec (13 x)

\int \frac{16 x ^{2}}{( x - 21 ) ( x + 7 ) ^{2}} d x

\frac{\partial}{\partial x} (\frac{2 x}{x ^{2} + y - 5})

\frac{d y}{d x} = b \cdot (1 - y) \cdot y

What is the tangent of x^2+y^2=25,(3,4) ?
The tangent of x^2+y^2=25,(3,4) is y=-3/4 x+25/4