What is the solution for 2t(dy)/(dt)+y=t^3 ?

The solution for 2t(dy)/(dt)+y=t^3 is y=(t^3)/7+(c_{1})/(sqrt(t))

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2t(dy)/(dt)+y=t^3

2 t \frac{d y}{d t} + y = t^{3}

y = \frac{t ^{3}}{7} + \frac{c _{1}}{t}

Solution steps

2 t \frac{d y}{d t} + y = t^{3}

Solve linear ODE:

y = \frac{t ^{3}}{7} + \frac{c _{1}}{t}

y = \frac{t ^{3}}{7} + \frac{c _{1}}{t}

\frac{( x ^{2} - 8 x - 17 )}{( x + 2 )}

cos (e^{x^{4} c o s (x)})

\int cot^{5} (2 t) d t

y = \frac{1}{2} 3 x

2 y^{^{''}} + y^{^{'}} + y = 0

What is the solution for 2t(dy)/(dt)+y=t^3 ?
The solution for 2t(dy)/(dt)+y=t^3 is y=(t^3)/7+(c_{1})/(sqrt(t))