What is the solution for (dy)/(dx)=((x^3+2y^3))/(xy^2) ?

The solution for (dy)/(dx)=((x^3+2y^3))/(xy^2) is y=x\sqrt[3]{-1+c_{1}x^3}

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(dy)/(dx)=((x^3+2y^3))/(xy^2)

\frac{d y}{d x} = \frac{( x ^{3} + 2 y ^{3} )}{x y ^{2}}

y = x 3 - 1 + c_{1} x^{3}

Solution steps

\frac{d y}{d x} = \frac{( x ^{3} + 2 y ^{3} )}{x y ^{2}}

Solve Bernoulli ODE:

y = x 3 - 1 + c_{1} x^{3}

y = x 3 - 1 + c_{1} x^{3}

x^{(\frac{1}{2})}

x \to 0 + lim (2 x - 1)

\frac{d}{d x} (n ln (\frac{1}{x}))

\frac{\partial}{\partial x} (\frac{47 x ^{2}}{( x - y ) ^{2}})

\int \frac{x}{x ^{2} + y ^{2}} d x

What is the solution for (dy)/(dx)=((x^3+2y^3))/(xy^2) ?
The solution for (dy)/(dx)=((x^3+2y^3))/(xy^2) is y=x\sqrt[3]{-1+c_{1}x^3}