What is the derivative of f(x)=2e^{3-4x} ?

The derivative of f(x)=2e^{3-4x} is -8e^{3-4x}

What is the first derivative of f(x)=2e^{3-4x} ?

The first derivative of f(x)=2e^{3-4x} is -8e^{3-4x}

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derivative of

f (x) = 2 e^{3 - 4 x}

- 8 e^{3 - 4 x}

Solution steps

\frac{d}{d x} (2 e^{3 - 4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{3 - 4 x})

Apply the chain rule:

e^{3 - 4 x} \frac{d}{d x} (3 - 4 x)

= e^{3 - 4 x} \frac{d}{d x} (3 - 4 x)

\frac{d}{d x} (3 - 4 x) = - 4

= 2 e^{3 - 4 x} (- 4)

Simplify

= - 8 e^{3 - 4 x}

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What is the derivative of f(x)=2e^{3-4x} ?
The derivative of f(x)=2e^{3-4x} is -8e^{3-4x}
What is the first derivative of f(x)=2e^{3-4x} ?
The first derivative of f(x)=2e^{3-4x} is -8e^{3-4x}