What is the sum from n=0 to infinity of (n^4)/(3^n) ?

The sum from n=0 to infinity of (n^4)/(3^n) is converges

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sum from n=0 to infinity of (n^4)/(3^n)

n = 0 \sum \infty \frac{n ^{4}}{3 ^{n}}

converges

Solution steps

n = 0 \sum \infty \frac{n ^{4}}{3 ^{n}}

Apply Series Ratio Test:

converges

= converges

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What is the sum from n=0 to infinity of (n^4)/(3^n) ?
The sum from n=0 to infinity of (n^4)/(3^n) is converges