What is the derivative of sqrt(x)+sqrt(y)+6 ?

The derivative of sqrt(x)+sqrt(y)+6 is 1/(2sqrt(x))

What is the first derivative of sqrt(x)+sqrt(y)+6 ?

The first derivative of sqrt(x)+sqrt(y)+6 is 1/(2sqrt(x))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

x + y + 6

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (x + y + 6)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x) + \frac{d}{d x} (y) + \frac{d}{d x} (6)

\frac{d}{d x} (x) = \frac{1}{2 x}

\frac{d}{d x} (y) = 0

\frac{d}{d x} (6) = 0

= \frac{1}{2 x} + 0 + 0

Simplify

= \frac{1}{2 x}

\int_{0}^{8} e^{- 0.25 t} d t

\int sin (3 x) sin (6 x) d x

[x^{2} (x^{2} + 8 x)]^{6}

x^{2} \frac{d y}{d x} = y^{2}

\frac{x ^{4}}{16} + \frac{1}{2 x ^{2}}

What is the derivative of sqrt(x)+sqrt(y)+6 ?
The derivative of sqrt(x)+sqrt(y)+6 is 1/(2sqrt(x))
What is the first derivative of sqrt(x)+sqrt(y)+6 ?
The first derivative of sqrt(x)+sqrt(y)+6 is 1/(2sqrt(x))