What is (\partial)/(\partial t)(-3s^2t^2) ?

The answer to (\partial)/(\partial t)(-3s^2t^2) is -6s^2t

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(\partial)/(\partial t)(-3s^2t^2)

\frac{\partial}{\partial t} (- 3 s^{2} t^{2})

- 6 s^{2} t

Solution steps

\frac{\partial}{\partial t} (- 3 s^{2} t^{2})

Treat

s

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 3 s^{2} \frac{\partial}{\partial t} (t^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 3 s^{2} \cdot 2 t^{2 - 1}

Simplify

= - 6 s^{2} t

\frac{d}{d x} ((10 x^{2} - 20 x + 20) e^{x})

\frac{d}{d x} (x (x^{2} + 8))

\int sin (x) + e^{x} d x

\frac{( 3 s + 4 )}{( s + 2 ) ^{2}}

x \to \infty lim (7 x^{2} + 3 x^{3})

What is (\partial)/(\partial t)(-3s^2t^2) ?
The answer to (\partial)/(\partial t)(-3s^2t^2) is -6s^2t