What is the tangent of f(x)=(x^2)/(x+3),(3, 3/2) ?

The tangent of f(x)=(x^2)/(x+3),(3, 3/2) is y= 3/4 x-3/4

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tangent of f(x)=(x^2)/(x+3),(3, 3/2)

tangent of

f (x) = \frac{x ^{2}}{x + 3}, (3, \frac{3}{2})

y = \frac{3}{4} x - \frac{3}{4}

Solution steps

Find the slope of

f (x) = \frac{x ^{2}}{x + 3} : \frac{df ( x )}{d x} = \frac{x ^{2} + 6 x}{( x + 3 ) ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{4}

Find the line with slope m=

\frac{3}{4}

and passing through

(3, \frac{3}{2}) : y = \frac{3}{4} x - \frac{3}{4}

y = \frac{3}{4} x - \frac{3}{4}

\int tan^{2} (x) sec (x) d x

arcsin (9 x + 9 y)

\int 6 x + 3 x^{2} + 12 x^{3} + C d x

\frac{( 3 t ^{2} + 4 )}{4 t + 4}

\int \frac{csc ( θ ) cot ( θ )}{9} d θ

What is the tangent of f(x)=(x^2)/(x+3),(3, 3/2) ?
The tangent of f(x)=(x^2)/(x+3),(3, 3/2) is y= 3/4 x-3/4