What is the integral of (csc(θ)cot(θ))/9 ?

The integral of (csc(θ)cot(θ))/9 is -1/9 csc(θ)+C

Popular >

integral of (csc(θ)cot(θ))/9

\int \frac{csc ( θ ) cot ( θ )}{9} d θ

- \frac{1}{9} csc (θ) + C

Solution steps

\int \frac{csc ( θ ) cot ( θ )}{9} d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{9} \cdot \int csc (θ) cot (θ) d θ

Apply u-substitution

: \int - 1 d u

= \frac{1}{9} \cdot \int - 1 d u

Integral of a constant:

\int a d x = a x

= \frac{1}{9} (- 1) u

Substitute back

u = csc (θ)

= \frac{1}{9} (- 1) csc (θ)

Simplify

= - \frac{1}{9} csc (θ)

Add a constant to the solution

= - \frac{1}{9} csc (θ) + C

\frac{d}{d x} (ln (1 + 7 x))

\frac{d}{d x} (x^{2} 4 x - 9)

\int - cos (u) + \frac{1}{3} cos^{3} (u) d u

(3 x^{2} - 10)^{- 13}

\int (- 3 (\frac{9 x ^{2}}{2}) - 4 x^{3}) d x

What is the integral of (csc(θ)cot(θ))/9 ?
The integral of (csc(θ)cot(θ))/9 is -1/9 csc(θ)+C