What is the integral of (x^2)/((1+x^3)) ?

The integral of (x^2)/((1+x^3)) is 1/3 ln|1+x^3|+C

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integral of (x^2)/((1+x^3))

\int \frac{x ^{2}}{( 1 + x ^{3} )} d x

\frac{1}{3} ln 1 + x^{3} + C

Solution steps

\int \frac{x ^{2}}{1 + x ^{3}} d x

Apply u-substitution

: \int \frac{1}{3 u} d u

= \int \frac{1}{3 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{3} ln ∣ u ∣

Substitute back

u = 1 + x^{3}

= \frac{1}{3} ln 1 + x^{3}

Add a constant to the solution

= \frac{1}{3} ln 1 + x^{3} + C

\int_{0}^{\frac{4}{3}} π (4 - 3 x)^{2} d x

z \to \frac{1}{2} lim (\frac{3 z + 1}{2 z - 5})

\int (2 - 2 y) d y

\frac{\partial}{\partial y} (8 x e^{x^{2} + y^{2}})

f (x) = 4 x

What is the integral of (x^2)/((1+x^3)) ?
The integral of (x^2)/((1+x^3)) is 1/3 ln|1+x^3|+C