What is (\partial)/(\partial t)(e^{2x}-xcos(t)) ?

The answer to (\partial)/(\partial t)(e^{2x}-xcos(t)) is xsin(t)

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(\partial)/(\partial t)(e^{2x}-xcos(t))

\frac{\partial}{\partial t} (e^{2 x} - x cos (t))

x sin (t)

Solution steps

\frac{\partial}{\partial t} (e^{2 x} - x cos (t))

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial t} (e^{2 x}) - \frac{\partial}{\partial t} (x cos (t))

\frac{\partial}{\partial t} (e^{2 x}) = 0

\frac{\partial}{\partial t} (x cos (t)) = - x sin (t)

= 0 - (- x sin (t))

Simplify

= x sin (t)

f (x) = x^{2} + 8 x - 2

x \to 0.9 lim (x^{2} - 1)

y = 13 x e^{x}

\frac{d y}{d x} - \frac{2 x ^{3} y}{x ^{4} + 3} = x^{3}

\frac{d}{d x} (2 A x + B)

What is (\partial)/(\partial t)(e^{2x}-xcos(t)) ?
The answer to (\partial)/(\partial t)(e^{2x}-xcos(t)) is xsin(t)