What is the derivative of (x^2-64/(x-8)) ?

The derivative of (x^2-64/(x-8)) is 1

What is the first derivative of (x^2-64/(x-8)) ?

The first derivative of (x^2-64/(x-8)) is 1

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\frac{d}{d x} (\frac{x ^{2} - 64}{x - 8})

1

Solution steps

\frac{d}{d x} (\frac{x ^{2} - 64}{x - 8})

Simplify

\frac{x ^{2} - 64}{x - 8} : x + 8

= \frac{d}{d x} (x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} + \frac{d}{d x} (8)

\frac{d x}{d x} = 1

\frac{d}{d x} (8) = 0

= 1 + 0

Simplify

= 1

f (x) = 3 - x

x \to - 1 lim (π)

x \to - 9 lim (50)

\int \frac{1}{sec ( t ) + tan ( t )} d t

n = 1 \sum \infty \frac{1}{5 n + 1}

What is the derivative of (x^2-64/(x-8)) ?
The derivative of (x^2-64/(x-8)) is 1
What is the first derivative of (x^2-64/(x-8)) ?
The first derivative of (x^2-64/(x-8)) is 1