What is the sum from n=1 to infinity of 1/(5n+1) ?

The sum from n=1 to infinity of 1/(5n+1) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=1 to infinity of 1/(5n+1)

n = 1 \sum \infty \frac{1}{5 n + 1}

diverges

Solution steps

n = 1 \sum \infty \frac{1}{5 n + 1}

Apply Series Integral Test:

diverges

= diverges

\int (x x + 1) d x

0.9 x^{2} + 6, x, (- 4, 4)

\frac{d y}{d x} = e^{2 x} + 4 y

\frac{d}{d x} (3 x + 2 x^{2})

\frac{d y}{d t} = (e^{- 2 t + 3 y})

What is the sum from n=1 to infinity of 1/(5n+1) ?
The sum from n=1 to infinity of 1/(5n+1) is diverges