What is area y=sin^2(x),y=sin^3(x),0<= x<= pi ?

The answer to area y=sin^2(x),y=sin^3(x),0<= x<= pi is pi/2-4/3

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area y=sin^2(x),y=sin^3(x),0<= x<= pi

area

y = sin^{2} (x), y = sin^{3} (x), 0 \leq x \leq π

\frac{π}{2} - \frac{4}{3}

Decimal

0.23746 \dots

Solution steps

Apply the area formula:

\int_{0}^{π} sin^{2} (x) - sin^{3} (x) d x

Solve

\int_{0}^{π} sin^{2} (x) - sin^{3} (x) d x : \frac{π}{2} - \frac{4}{3}

The area is:

= \frac{π}{2} - \frac{4}{3}

[x^{2} + y^{2}] d x = x y d y

k = 0 \sum \infty (\frac{4}{5})^{k}

- \frac{1}{( x + 1 ) ^{2}}

\int (\frac{e ^{x}}{x}) d x

n = 1 \sum \infty \frac{1 ^{n}}{n + 1}

What is area y=sin^2(x),y=sin^3(x),0<= x<= pi ?
The answer to area y=sin^2(x),y=sin^3(x),0<= x<= pi is pi/2-4/3