What is (\partial)/(\partial r)(pir^2h) ?

The answer to (\partial)/(\partial r)(pir^2h) is 2pihr

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(\partial)/(\partial r)(pir^2h)

\frac{\partial}{\partial r} (π r^{2} h)

2 πh r

Solution steps

\frac{\partial}{\partial r} (π r^{2} h)

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= πh \frac{\partial}{\partial r} (r^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= πh \cdot 2 r^{2 - 1}

Simplify

= 2 πh r

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\frac{\partial}{\partial y} (sin (x) + e^{x y})

\frac{d}{d x} ((ln (4 x))^{2})

What is (\partial)/(\partial r)(pir^2h) ?
The answer to (\partial)/(\partial r)(pir^2h) is 2pihr