What is the (-x^2sin(x)+2pixsin(x)-2picos(x)+2pi)^' ?

The (-x^2sin(x)+2pixsin(x)-2picos(x)+2pi)^' is -x^2cos(x)+2pixcos(x)-2xsin(x)+4pisin(x)

What is the first (-x^2sin(x)+2pixsin(x)-2picos(x)+2pi)^' ?

The first (-x^2sin(x)+2pixsin(x)-2picos(x)+2pi)^' is -x^2cos(x)+2pixcos(x)-2xsin(x)+4pisin(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(- x^{2} sin (x) + 2 π x sin (x) - 2 π cos (x) + 2 π)^{^{'}}

- x^{2} cos (x) + 2 π x cos (x) - 2 x sin (x) + 4 π sin (x)

Solution steps

(- x^{2} sin (x) + 2 π x sin (x) - 2 π cos (x) + 2 π)^{'}

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - (x^{2} sin (x))^{^{'}} + (2 π x sin (x))^{^{'}} - (2 π cos (x))^{^{'}} + (2 π)^{^{'}}

(x^{2} sin (x))^{'} = 2 x sin (x) + cos (x) x^{2}

(2 π x sin (x))^{'} = 2 π (sin (x) + x cos (x))

(2 π cos (x))^{'} = - 2 π sin (x)

(2 π)^{'} = 0

= - (2 x sin (x) + cos (x) x^{2}) + 2 π (sin (x) + x cos (x)) - (- 2 π sin (x)) + 0

Simplify

- (2 x sin (x) + cos (x) x^{2}) + 2 π (sin (x) + x cos (x)) - (- 2 π sin (x)) + 0 : - x^{2} cos (x) + 2 π x cos (x) - 2 x sin (x) + 4 π sin (x)

= - x^{2} cos (x) + 2 π x cos (x) - 2 x sin (x) + 4 π sin (x)

\frac{d}{d x} (\frac{1 + cos ( x )}{2})

\int e^{x} sin (6 x) d x

\frac{d}{d x} (\frac{x ^{3} + 2}{3})

\int e^{6 x} cos (2 x) d x

\frac{d}{d x} (\frac{4}{4 x})

What is the (-x^2sin(x)+2pixsin(x)-2picos(x)+2pi)^' ?
The (-x^2sin(x)+2pixsin(x)-2picos(x)+2pi)^' is -x^2cos(x)+2pixcos(x)-2xsin(x)+4pisin(x)
What is the first (-x^2sin(x)+2pixsin(x)-2picos(x)+2pi)^' ?
The first (-x^2sin(x)+2pixsin(x)-2picos(x)+2pi)^' is -x^2cos(x)+2pixcos(x)-2xsin(x)+4pisin(x)