What is the sum from n=1 to infinity of 1/(n^{5/2)} ?

The sum from n=1 to infinity of 1/(n^{5/2)} is converges

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sum from n=1 to infinity of 1/(n^{5/2)}

n = 1 \sum \infty \frac{1}{n ^{\frac{5}{2}}}

converges

Solution steps

n = 1 \sum \infty \frac{1}{n ^{\frac{5}{2}}}

Apply p-Series Test:

converges

= converges

\frac{4}{( s ( s ^{2} + 4 ) )}

(- 1, - 7), (3, 9)

n = 0 \sum \infty 9 (- 0.8)^{n}

\frac{d}{d x} (\frac{1}{3} (2 + x^{2})^{\frac{3}{2}})

\int_{1}^{5} \frac{4}{x ^{2}} d x

What is the sum from n=1 to infinity of 1/(n^{5/2)} ?
The sum from n=1 to infinity of 1/(n^{5/2)} is converges