What is area |20x+x^2-x^3|,y=0,[-4,5] ?

The answer to area |20x+x^2-x^3|,y=0,[-4,5] is 2521/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

area |20x+x^2-x^3|,y=0,[-4,5]

area

20 x + x^{2} - x^{3}, y = 0, [- 4, 5]

\frac{2521}{12}

Decimal

210.08333 \dots

Solution steps

Apply the area formula:

\int_{- 4}^{5} - x^{3} + x^{2} + 20 x d x

Solve

\int_{- 4}^{5} - x^{3} + x^{2} + 20 x d x : \frac{2521}{12}

The area is:

= \frac{2521}{12}

x^{2} + 4 x - 5, - x^{2} + 4 x + 3

x \to 1 lim (4 x^{2})

\int \frac{1}{( sin ( 4 x ) ) ^{2}} d x

\frac{d}{d x} (- \frac{2 ( - 3 x ^{2} + 1 )}{( 1 + x ^{2} ) ^{3}})

\frac{x ^{4} - x + 1}{x ^{4} + x + 1}

What is area |20x+x^2-x^3|,y=0,[-4,5] ?
The answer to area |20x+x^2-x^3|,y=0,[-4,5] is 2521/12