What is the limit as x approaches 0 of x^2ln(4x^2) ?

The limit as x approaches 0 of x^2ln(4x^2) is 0

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limit as x approaches 0 of x^2ln(4x^2)

x \to 0 lim (x^{2} ln (4 x^{2}))

0

Solution steps

x \to 0 lim (x^{2} ln (4 x^{2}))

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 0 - lim (x^{2} ln (4 x^{2})) = 0

x \to 0 + lim (x^{2} ln (4 x^{2})) = 0

= 0

\frac{1}{4 s ^{3}}

\frac{\partial}{\partial x} (1 - x^{2} - x - 3 y^{2} + y)

\frac{\partial}{\partial x} (x y - 4 x^{2} y)

y^{^{'}} = 4 y + x^{2} + 9

\int (3^{x} - sec^{2} (x)) d x

What is the limit as x approaches 0 of x^2ln(4x^2) ?
The limit as x approaches 0 of x^2ln(4x^2) is 0