What is the solution for (dy}{dx}=\frac{2y)/x ,x>0 ?

The solution for (dy}{dx}=\frac{2y)/x ,x>0 is y=c_{1}x^2

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(dy}{dx}=\frac{2y)/x ,x>0

\frac{d y}{d x} = \frac{2 y}{x}, x > 0

y = c_{1} x^{2}

Solution steps

\frac{d y}{d x} = \frac{2 y}{x}

Solve separable ODE:

y = c_{1} x^{2}

y = c_{1} x^{2}

\frac{d}{d x} (\frac{x}{( 1 + 2 x ) ^{2}})

\frac{\partial}{\partial x} (ln (x + y^{3} + x y^{2}))

\frac{\partial}{\partial z} (x^{2} y z^{2})

\frac{d}{d x} (1 - \frac{3}{x + 7})

\frac{d}{d x} (cos (e^{3 x}))

What is the solution for (dy}{dx}=\frac{2y)/x ,x>0 ?
The solution for (dy}{dx}=\frac{2y)/x ,x>0 is y=c_{1}x^2