What is the derivative of sec^2(2x-tan^2(2x)) ?

The derivative of sec^2(2x-tan^2(2x)) is 0

What is the first derivative of sec^2(2x-tan^2(2x)) ?

The first derivative of sec^2(2x-tan^2(2x)) is 0

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\frac{d}{d x} (sec^{2} (2 x) - tan^{2} (2 x))

0

Solution steps

\frac{d}{d x} (sec^{2} (2 x) - tan^{2} (2 x))

sec^{2} (2 x) - tan^{2} (2 x) = 1

= \frac{d}{d x} (1)

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

\int \frac{28 x ^{2}}{4 - x ^{2}} d x

\int \frac{x ^{3}}{( x ^{2} + 4 x + 5 ) ^{2}} d x

\int \frac{x ^{2} + 2 x}{x + 1} d x

\frac{d}{d x} (- 2^{x})

(\frac{x}{4 x - 3 ln ( x )})^{^{'}}

What is the derivative of sec^2(2x-tan^2(2x)) ?
The derivative of sec^2(2x-tan^2(2x)) is 0
What is the first derivative of sec^2(2x-tan^2(2x)) ?
The first derivative of sec^2(2x-tan^2(2x)) is 0