What is the derivative of-2^x ?

The derivative of-2^x is -2^xln(2)

What is the first derivative of-2^x ?

The first derivative of-2^x is -2^xln(2)

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\frac{d}{d x} (- 2^{x})

- 2^{x} ln (2)

Solution steps

\frac{d}{d x} (- 2^{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - \frac{d}{d x} (2^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= - 2^{x} ln (2)

(\frac{x}{4 x - 3 ln ( x )})^{^{'}}

\frac{5 s + 31}{s ^{2} + 6 s + 9}

\int_{1}^{3} x^{- 2} d x

x \to 2 + lim (\frac{5}{x - 2})

x \to \infty lim (- 2)