What is the integral from 1 to 3 of x^{-2} ?

The integral from 1 to 3 of x^{-2} is 2/3

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integral from 1 to 3 of x^{-2}

\int_{1}^{3} x^{- 2} d x

\frac{2}{3}

Decimal

0.66666 \dots

Solution steps

\int_{1}^{3} x^{- 2} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{3}

= [- \frac{1}{x}]_{1}^{3}

Compute the boundaries:

\frac{2}{3}

= \frac{2}{3}

x \to 2 + lim (\frac{5}{x - 2})

x \to \infty lim (- 2)

\int y cos (x y) - 3 y^{2} + e^{x} d x

x = - 2, x = 3, y = x^{2} - 3, y = 2 x

e^{5 x + 5}, 0

What is the integral from 1 to 3 of x^{-2} ?
The integral from 1 to 3 of x^{-2} is 2/3