What is the derivative of (2x)/(e^x) ?

The derivative of (2x)/(e^x) is (2(1-x))/(e^x)

What is the first derivative of (2x)/(e^x) ?

The first derivative of (2x)/(e^x) is (2(1-x))/(e^x)

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derivative of

\frac{2 x}{e ^{x}}

\frac{2 ( 1 - x )}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{2 x}{e ^{x}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{x}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 2 \cdot \frac{\frac{d x}{d x} e ^{x} - \frac{d}{d x} ( e ^{x} ) x}{( e ^{x} ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (e^{x}) = e^{x}

= 2 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}}

Simplify

2 \cdot \frac{1 \cdot e ^{x} - e ^{x} x}{( e ^{x} ) ^{2}} : \frac{2 ( 1 - x )}{e ^{x}}

= \frac{2 ( 1 - x )}{e ^{x}}

2 y y^{^{'}} + 4 = y^{2} + 4 x, y (0) = 5

t \to 0 lim (sin (3 t))

\int \frac{4 - x ^{2}}{2} d x

\frac{d}{d x} (x^{3} - 9 x^{2} + 24 x)

n = 1 \sum \infty \frac{2 ^{n}}{n ^{2}}

What is the derivative of (2x)/(e^x) ?
The derivative of (2x)/(e^x) is (2(1-x))/(e^x)
What is the first derivative of (2x)/(e^x) ?
The first derivative of (2x)/(e^x) is (2(1-x))/(e^x)